LimestoneRock 17:23 16 Mar 2012
Locked

Sorry to post this query here but I did not know where else I could go:

20° C = 68.00° F 19° C = 66.20° F ie (19 x 9 ÷ 5) + 32. However, 1° C = 33.80° F ie (1 x 9 ÷ 5) + 32. Therefore, 20° C minus 1° C = 19° C So: 68.00° F minus 33.80° F = 34.20° F = 19° C BUT 19° C = 66.20° F Can anyone explain please? Am I being stupid and missing something? I don't think my format is going to reproduce very well when translated to this Forum.

wiz-king 18:03 16 Mar 2012

however 34.2 f (-32 x 5/9) = 1.2C

You have to take the away the 32 from the F first when converting F to C

Fruit Bat /\0/\ 21:08 16 Mar 2012

C=5/9 (F-32)

F=(9/5C) +32

natdoor 21:27 16 Mar 2012

20° C minus 1° C = 19° C

So: 68.00° F minus 33.80° F = 34.20° F = 19° C.

You have taken the Fahrenheit equivalent of a temperature of 1° C (33.80° F) as the equivalent to reducing the temperature by 1° C. This is patently incorrect. A change of temperature of 1° C is the equvalent of a change of 1.8° F. Therefore:-

68.00° F minus 1.80° F = 66.20° F = 19° C.

OTT_B 21:37 16 Mar 2012

LimestoneRock

natdoor's explanation is perfect (as are the other two).

And there is no 'degrees' for Franenheit, so it's 19F, not 19°F

Lecture over.

OTT_B 21:41 16 Mar 2012

lotvic 22:00 16 Mar 2012

Why is there no 'degrees' for Fahrenheit, so it's 19F, not 19°F? The degree °F mark is on my room thermometer.

lotvic 22:07 16 Mar 2012

and it says on Wikipedia "...the Celsius scale (known until 1948 as centigrade) replaced Fahrenheit in many countries, typically during their metrication process"

OTT_B 22:12 16 Mar 2012

You've highlighted the right part of the wikipedia article.....the name changed - Celsius, not centigrade!

As for °F, I might need to retract from my position on this. I've got some old notes which make it very clear that there is no 'degrees' for Fahrenheit, but it seems that the lecturer may have been wrong (he was however correct about centigrade!!)

Strawballs 00:07 17 Mar 2012

I just use the converter on my phone much easier?

LimestoneRock 00:52 17 Mar 2012

I understand, just about, what is being said but I still do not get it. I am not talking about the equivalent to reducing the temperature by 1° C - I am just showing arithmetical facts and calulations in my poser. Thanks very much everyone for your comments.

This thread is now locked and can not be replied to.

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