MATHEMATICS PROBLEM

  Poloman69 18:28 12 Feb 2004
Locked

I know this is meant for PC questions, but i thought i would have a stab in the dark here as computing is mathematics after all.

I am trying to find if there are any maths forums online.

I need to solve the following equation urgently:

x - 5 1
----- + - = 0
x + 1 x

CAN ANYONE HELP ????

(Showing workings out will win you EXTRA Brownie points with me)

  s99Raj 18:34 12 Feb 2004

I'm a Mathematician with a Masters in Maths.
Sorry, but your equation doesn't make sense. Try again.

Not sure what the first part means, but surely 0x + 1x is 1x?

  Poloman69 18:37 12 Feb 2004

Sorry

It should show


(x-5) 1 .
----- + - = 0 .
(x+1) x .




OR

( x - 5 ) / (x + 1) + 1 / x = 0

(in case PCA won't edit it correctly)

  Poloman69 18:39 12 Feb 2004

s99Raj

It's meant to look like a quadratic equation

(x-5) over (x+1) PLUS 1 over x which equals '0'

  s99Raj 18:39 12 Feb 2004

Aha! That's better. And dead easy too.
If you hold on a second I'll tell you.
P.S. How old are you? The question sounds like a typical GCSE question.

  Poloman69 18:40 12 Feb 2004

It's for my son and i haven't done these in 15 years or so

  Poloman69 18:41 12 Feb 2004

It's for my son and i haven't done these in 15 years or so

  s99Raj 18:45 12 Feb 2004

Multiply the whole thing by x(x+1) to give you
x(x-5) + x + 1 = 0, which multiplies out to give
x^2 - 4x = 1 = 0.

Use the formula for a quadratic to get the two solutions
x = 2 + (Square Root of 2)
or
x = 2 - (Square Root of 2)

  s99Raj 18:46 12 Feb 2004

Whoops! I meant

Use the formula for a quadratic to get the two solutions x = 2 + (Square Root of 3) or x = 2 - (Square Root of 3)

  s99Raj 18:49 12 Feb 2004

My typing's funny. Let's try again :

Multiply the whole thing by x(x+1) to give you x(x-5) + x + 1 = 0, which multiplies out to give x^2 - 4x + 1 = 0.

Use the formula for a quadratic to get the two solutions x = 2 + (Square Root of 3) or x = 2 - (Square Root of 3)

The two solutions are about 3.732 or 0.268

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