Sorry it's not an IT question but I'm struggling.x = 104,300 + 1/30yy = 59,600 + 18/90xThanks hopefully.
42.The answer to all mathematical questions is always 42.;o)(Sorry I can't help!)
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x = 104,300 + 1/30yreplace "y" in the above with what you know "y" to be...x = 104,300 + 1/30(59,600 + 18/90x)Rearrange tis to get all the X on one side and you should be away...Regards,Simsy
18/90x = 59600-yx = (59600-y)90/18x = 298000-90/18y:. 298000-90/18y = 1043001/30y 298000-104300 = (1/30+90/18)y 193700 = (3/90+450/90)y Y = 193700*90/453 Y = 38483.44AND X = 105582.78 I think!!!!
Simsy is correctElectroplater starts off incorrect - if you take 59,600 off both sides of the 2nd equation you gety-15600=18/90x (or 18/90x=y-15600)
For 15,600 read 59,600. Oops!
Odd equations involving very large numbers leading to a quadratic equation to solve. Are you sure you are starting off correct?
The answer:x = 107,000y = 81,000
If your equations are correct to start with, following simsy's lead, I got as far asx2 + 193700x - 31081400000 = 0(where x2 is x squared)Then you have to use the standard solution to quadratic equations, which I can't type in here!
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