Anyone any good at Algebra please?

  Halmer 18:06 11 Apr 2010
Locked

Sorry it's not an IT question but I'm struggling.

x = 104,300 + 1/30y

y = 59,600 + 18/90x

Thanks hopefully.

  Pineman100 18:17 11 Apr 2010

42.

The answer to all mathematical questions is always 42.

;o)

(Sorry I can't help!)

  eedcam 18:46 11 Apr 2010

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  rdave13 18:48 11 Apr 2010

Any help? click here

  Simsy 18:53 11 Apr 2010

x = 104,300 + 1/30y

replace "y" in the above with what you know "y" to be...

x = 104,300 + 1/30(59,600 + 18/90x)

Rearrange tis to get all the X on one side and you should be away...

Regards,

Simsy

  electroplater 18:56 11 Apr 2010

18/90x = 59600-y
x = (59600-y)90/18
x = 298000-90/18y

:. 298000-90/18y = 1043001/30y
298000-104300 = (1/30+90/18)y
193700 = (3/90+450/90)y
Y = 193700*90/453

Y = 38483.44

AND X = 105582.78

I think!!!!

  ame 19:04 11 Apr 2010

Simsy is correct
Electroplater starts off incorrect - if you take 59,600 off both sides of the 2nd equation you get
y-15600=18/90x (or 18/90x=y-15600)

  ame 19:08 11 Apr 2010

For 15,600 read 59,600. Oops!

  ame 19:40 11 Apr 2010

Odd equations involving very large numbers leading to a quadratic equation to solve. Are you sure you are starting off correct?

  Sea Urchin 19:52 11 Apr 2010

The answer:

x = 107,000

y = 81,000

  ame 19:55 11 Apr 2010

If your equations are correct to start with, following simsy's lead, I got as far as

x2 + 193700x - 31081400000 = 0

(where x2 is x squared)

Then you have to use the standard solution to quadratic equations, which I can't type in here!

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